frieren the slayer (ram2n)@last_great_mage • 3d√(1³) = 1√(1³+2³) = 1+2√(1³+2³+3³) = 1+2+3√(1³+2³+3³+4³) = 1+2+3+4
@last_great_mage • 3d
C.C@based3dReplying to @last_great_magewhaat? no way100271